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require.d

require-dir

Require all modules in a directory

Not use module.parent,to avoid module cache

获取一个目录内的所有模块

不使用module.parent, 避免模块缓存

example

'use strict'
const rd= require('require.d')

const test = rd(__dirname + '/test');

console.log(test)

result

{ a: { f3: [Function] }, f1: [Function], f2: [Function] }