A simple (?) solution to the fairly common problem of lateration.
You've got three or more beacons, their distances to your device and you want to calculate the device's position.
Suppose we have three circles, and somewhere in their center our beacon. The radius of each circle is the (approximate) distance to the beacon. Let call the circles A, B, and C.
Each circle's formula would look like this:
Substracting two circles would give a linear equation, which crosses their two intersections:
Calculating the intersection of two of these linear equations gives the x-value of the devices position in between the beacons.
This value can then be inserted in one of the two linear equations to get the corresponding y-value.
This process is repeated for each pair of circles and for each pair lines resulting from this circle subtraction. The resulting points are averaged.
npm install lateration
;// The beaconsconst beacons =0 1 5894 7 4624 5 273;// Lateratingconst position = ;
var lateration = ;var Circle = laterationCircle;var Vector = laterationVector;var laterate = laterationlaterate;// The beaconsvar beacons =0 1 5894 7 4624 5 273;// Lateratingvar position = ;
Takes a list of Circles and executes a lateration operation.
If it can't generate enough lines to intersect, it will return null.
A simple vector with
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